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Chapter 8: Variable - Reluctance Machines and Stepping Motors

Module by: NGUYEN Phuc

Variable - Reluctance Machines
and Stepping Motors
This lecture note is based on the textbook # 1. Electric Machinery - A.E. Fitzgerald, Charles Kingsley, Jr., Stephen D. Umans- 6th edition- Mc Graw Hill series in Electrical Engineering. Power and Energy
  • Variable-reluctance machines (VRMs) are perhaps the simplest of electrical machines. They consist of a stator with excitation windings and a magnetic rotor with saliency. Rotor conductors are not required because torque is produced by the tendency of the rotor to align with the stator- produced flux wave in such a fashion as to maximize the stator flux linkages that result from a given applied stator current. Torque production in these machines can be evaluated by using the techniques of Chapter 3 and the fact that the stator winding inductances are functions of the angular position of the rotor.
  • Although the concept of the VRM has been around for a long time, only in the past few decades have these machines begun to see widespread use in engineering applications. This is due in large part to the fact that although they are simple in construction, they are somewhat complicated to control. The position of the rotor must be known in order to properly energize the phase windings to produce torque. It is the widespread availability and low cost of micro and power electronics that has made the VRM competitive with other motor technologies in a wide range of applications.
  • By sequentially exciting the phases of a VRM, the rotor will rotate in a step- wise fashion, rotating through a specific angle per step. Stepper motors are designed to take advantage of this characteristic. Such motors often combine the use of a variable-reluctance geometry with permanent magnets to produce increased torque and precision position accuracy.
8.1 BASICS OF VRM ANALYSIS
  • VRMs can be categorized into two types: singly- salient and doubly-salient. In both cases, their most noticeable features are that there are no windings or permanent magnets on their rotors and that their only source of excitation consists of stator windings.
  • To produce torque, VRMs must be designed such that the stator-winding inductances vary with the position of the rotor.
  • Figure 8.1a shows a cross-sectional view of a singly-salient VRM, which can be seen to consist of a nonsalient stator and a two-pole salient rotor, both constructed of high-permeability magnetic material. In the figure, a two-phase stator winding is shown although any number of phases is possible.
  • Figure 8.2a shows the form of the variation of the stator inductances as a function of rotor angle θm for a singly-salient VRM of the form of Fig. 8.1 a. Notice that the inductance of each stator phase winding varies with rotor position such that the inductance is maximum when the rotor axis is aligned with the magnetic axis of that phase and minimum when the two axes are perpendicular. The mutual inductance between the phase windings is zero when the rotor is aligned with the magnetic axis of either phase but otherwise varies periodically with rotor position.
  • Figure 8.lb shows the cross-sectional view of a two-phase doubly-salient VRM in which both the rotor and stator have salient poles. In this machine, the stator has four poles, each with a winding. However, the windings on opposite poles are of the same phase; they may be connected either in series or in parallel. Thus this machine is quite similar to that of Fig. 8.1a in that there is a two-phase stator winding and a two-pole salient rotor. Similarly, the phase inductance of this configuration varies from a maximum value when the rotor axis is aligned with the axis of that phase to a minimum when they are perpendicular.
  • Unlike the singly-salient machine of Fig. 8.1 a, under the assumption of negligible iron reluctance the mutual inductances between the phases of the doubly-salient VRM of Fig. 8.1 b will be zero, with the exception of a small, essentially-constant component associated with leakage flux. In addition, the saliency of the stator enhances the difference between the maximum and minimum inductances, which in turn enhances the torque-producing characteristics of the doubly-salient machine. Figure 8.2b shows the form of the variation of the phase inductances for the doubly-salient VRM of Fig. 8.lb.
  • The relationship between flux linkage and current for the singly-salient VRM is of the form
λ1λ2=L11(θm)L12(θm)L12(θm)L22(θm)i1i2λ1λ2=L11(θm)L12(θm)L12(θm)L22(θm)i1i2 size 12{ left [ matrix { λ rSub { size 8{1} } {} ## λ rSub { size 8{2} } } right ]= left [ matrix { L rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) {} # L rSub { size 8{"12"} } \( θ rSub { size 8{m} } \) {} ## L rSub { size 8{"12"} } \( θ rSub { size 8{m} } \) {} # L rSub { size 8{"22"} } \( θ rSub { size 8{m} } \) {} } right ] left [ matrix { i rSub { size 8{1} } {} ## i rSub { size 8{2} } } right ]} {}(8.1)
Here L11(θm)L11(θm) size 12{L rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) } {} and L22(θm)L22(θm) size 12{L rSub { size 8{"22"} } \( θ rSub { size 8{m} } \) } {} are the self-inductances of phases 1 and 2, respectively, and L12(θm)L12(θm) size 12{L rSub { size 8{"12"} } \( θ rSub { size 8{m} } \) } {} is the mutual inductances. Note that, by symmetry
L22(θm)=L11(θm900)L22(θm)=L11(θm900) size 12{L rSub { size 8{"22"} } \( θ rSub { size 8{m} } \) =L rSub { size 8{"11"} } \( θ rSub { size 8{m} } - "90" rSup { size 8{0} } \) } {}(8.2)
Figure 1
Figure 2
Figure 8.1 Basic two-phase VRMs: (a) singly-salient
and (b) doubly-salient.
Figure 3
Figure 8.2 Plots of inductance versus 0m for (a) the singly-salient
VRM of Fig. 8.1a and (b) the doubly-salient VRM of Fig. 8.1b.
  • These inductances are periodic with a period of 18001800 size 12{"180" rSup { size 8{0} } } {} because rotation of the rotor through 180o180o size 12{"180" rSup { size 8{o} } } {} from any given angular position results in no change in the magnetic circuit of the machine.
  • The electromagnetic torque of this system can be determined from the coenergy as
Tmech=Wfld'(i1,i2,θm)θmTmech=Wfld'(i1,i2,θm)θm size 12{T rSub { size 8{ ital "mech"} } = { { partial { {W}} sup { ' } rSub { size 8{ ital "fld"} } \( i rSub { size 8{1} } ,i rSub { size 8{2} } ,θ rSub { size 8{m} } \) } over { partial θ rSub { size 8{m} } } } } {}(8.3)
where the partial derivative is taken while holding currents i1i1 size 12{i rSub { size 8{1} } } {} and i2i2 size 12{i rSub { size 8{2} } } {} constant. Here, the coenergy can be found,
Wfld'=12L11(θm)i12+L12(θm)i1i2+12L22(θm)i22Wfld'=12L11(θm)i12+L12(θm)i1i2+12L22(θm)i22 size 12{ { {W}} sup { ' } rSub { size 8{ ital "fld"} } = { {1} over {2} } L rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) i rSub { size 8{1} } rSup { size 8{2} } +L rSub { size 8{"12"} } \( θ rSub { size 8{m} } \) i rSub { size 8{1} } i rSub { size 8{2} } + { {1} over {2} } L"" lSub { size 8{"22"} } \( θ rSub { size 8{m} } \) i rSub { size 8{2} } rSup { size 8{2} } } {}(8.4)
Thus, combining Eqs. 8.3 and 8.4 gives the torque as
Tmech=12i12dL11(θm)m+i1i2dL12(θm)m+12i22dL22(θm)mTmech=12i12dL11(θm)m+i1i2dL12(θm)m+12i22dL22(θm)m size 12{T rSub { size 8{ ital "mech"} } = { {1} over {2} } i rSub { size 8{1} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } +i rSub { size 8{1} } i rSub { size 8{2} } { { ital "dL" rSub { size 8{"12"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } + { {1} over {2} } i rSub { size 8{2} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"22"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } } {}(8.5)
  • For the double-salient VRM of Fig. 8. lb, the mutual-inductance term dL12(θm)/mdL12(θm)/m size 12{ ital "dL" rSub { size 8{"12"} } \( θ rSub { size 8{m} } \) /dθ rSub { size 8{m} } } {} is zero and the torque expression of Eq. 8.5 simplifies to
Tmech=12i12dL11(θm)m+12i22dL22(θm)mTmech=12i12dL11(θm)m+12i22dL22(θm)m size 12{T rSub { size 8{ ital "mech"} } = { {1} over {2} } i rSub { size 8{1} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } + { {1} over {2} } i rSub { size 8{2} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"22"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } } {}(8.6)
Substitution of Eq. 8.2 then gives
Tmech=12i12dL11(θm)m+12i22dL11(θm900)mTmech=12i12dL11(θm)m+12i22dL11(θm900)m size 12{T rSub { size 8{ ital "mech"} } = { {1} over {2} } i rSub { size 8{1} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } + { {1} over {2} } i rSub { size 8{2} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } - "90" rSup { size 8{0} } \) } over {dθ rSub { size 8{m} } } } } {}(8.7)
  • Equations 8.6 and 8.7 illustrate an important characteristic of VRMs in which mutual-inductance effects are negligible. In such machines the torque expression consists of a sum of terms, each of which is proportional to the square of an individual phase current. As a result, the torque depends only on the magnitude of the phase currents and not on their polarity. Thus the electronics which supply the phase currents to these machines can be unidirectional; i.e., bidirectional currents are not required.
  • Since the phase currents are typically switched on and off by solid-state switches such as transistors or thyristors and since each switch need only handle currents in a single direction, this means that the motor drive requires only half the number of switches (as well as half the corresponding control electronics) that would be required in a corresponding bidirectional drive. The result is a drive system which is less complex and may be less expensive.
  • The assumption of negligible mutual inductance is valid for the doubly-salient VRM of Fig.8.1b both due to symmetry of the machine geometry and due to the assumption of negligible iron reluctance. In practice, even in situations where symmetry might suggest that the mutual inductances are zero or can be ignored because they are independent of rotor position (e.g., the phases are coupled through leakage fluxes), significant nonlinear and mutual-inductance effects can arise due to saturation of the machine iron.
  • At the design and analysis stage, the winding flux-current relationships and the motor torque can be determined by using numerical-analysis packages which can account for the nonlinearity of the machine magnetic material. Once a machine has been constructed, measurements can be made, both to validate the various assumptions and approximations which were made as well as to obtain an accurate measure of actual machine performance.
  • The symbol Ps is used to indicate the number of stator poles and PrPr size 12{P rSub { size 8{r} } } {} to indicate the number of rotor poles, and the corresponding machine is called a Ps/PrPs/Pr size 12{P rSub { size 8{s} } /P rSub { size 8{r} } } {} machine.
  • Example 8.1 examines a 4/2 VRM.
A 4/2 VRM is shown in Fig. 8.3. Its dimensions are
R = 3.8 cm α=β=60o=π/3α=β=60o=π/3 size 12{α=β="60" rSup { size 8{o} } =π/3} {} rad
g = 2.54 x 102102 size 12{"10" rSup { size 8{ - 2} } } {} cm D = 13.0 cm
and the poles of each phase winding are connected in series such that there are a total of N=100 turns (50 turns per pole) in each phase winding. Assume the rotor and stator to be of infinite magnetic permeability.
Figure 4
Figure 8.3 4/2 VRM for Example 8.1.
a. Neglecting leakage and fringing fluxes, plot the phase-1 inductance L(θm)L(θm) size 12{L \( θ rSub { size 8{m} } \) } {}as a function of θmθm size 12{θ rSub { size 8{m} } } {}.
b. Plot the torque, assuming (i) i1=I1i1=I1 size 12{i rSub { size 8{1} } =I rSub { size 8{1} } } {}and i2i2 size 12{i rSub { size 8{2} } } {} = 0 and (ii) i1i1 size 12{i rSub { size 8{1} } } {} = 0 and i2=I2i2=I2 size 12{i rSub { size 8{2} } =I rSub { size 8{2} } } {}.
c. Calculate the net torque (in N. m) acting on the rotor when both windings are excited such that i1=i2=i1=i2= size 12{i rSub { size 8{1} } =i rSub { size 8{2} } ={}} {}5 A and at angles (i) θm=0oθm=0o size 12{θ rSub { size 8{m} } =0 rSup { size 8{o} } } {}, (ii) θ=45oθ=45o size 12{θ="45" rSup { size 8{o} } } {}, (iii) θm=75oθm=75o size 12{θ rSub { size 8{m} } ="75" rSup { size 8{o} } } {}.
Solution
a. The maximum inductance LmaxLmax size 12{L rSub { size 8{"max"} } } {} for phase 1 occurs when the rotor axis is aligned with the phase-1 magnetic axis. LmaxLmax size 12{L rSub { size 8{"max"} } } {} is equal to
L max = N 2 μ o α RD 2g L max = N 2 μ o α RD 2g size 12{L rSub { size 8{"max"} } = { {N rSup { size 8{2} } μ rSub { size 8{o} } α ital "RD"} over {2g} } } {}
where αα size 12{α} {}RD is the cross-sectional area of the air gap and 2g is the total gap length in the magnetic circuit. For the values given,
L max = N 2 μ o α RD 2g L max = N 2 μ o α RD 2g size 12{L rSub { size 8{"max"} } = { {N rSup { size 8{2} } μ rSub { size 8{o} } α ital "RD"} over {2g} } } {}
= ( 100 ) 2 ( × 10 7 ) ( π / 3 ) ( 3 . 8 × 10 2 ) ( 0 . 13 ) 2 × ( 2 . 54 × 10 4 ) = ( 100 ) 2 ( × 10 7 ) ( π / 3 ) ( 3 . 8 × 10 2 ) ( 0 . 13 ) 2 × ( 2 . 54 × 10 4 ) size 12{ {}= { { \( "100" \) rSup { size 8{2} } \( 4π times "10" rSup { size 8{ - 7} } \) \( π/3 \) \( 3 "." 8 times "10" rSup { size 8{ - 2} } \) \( 0 "." "13" \) } over {2 times \( 2 "." "54" times "10" rSup { size 8{ - 4} } \) } } } {}
= 0 . 128 H = 0 . 128 H size 12{ {}=0 "." "128"H} {}
Neglecting fringing, the inductance L(θm)L(θm) size 12{L \( θ rSub { size 8{m} } \) } {}will vary linearly with the air-gap cross-sectional area as shown in Fig. 8.4a. Note that this idealization predicts that the inductance is zero when there is no overlap when in fact there will be some small value of inductance, as shown in Fig. 8.2.
Figure 5
Figure 8.4 (a) L11(θm)L11(θm) size 12{L rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) } {} versus θmθm size 12{θ rSub { size 8{m} } } {}, (b) dL11(θm)/mdL11(θm)/m size 12{ ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) /dθ rSub { size 8{m} } } {}versus θmθm size 12{θ rSub { size 8{m} } } {}, and (c) torque versus θmθm size 12{θ rSub { size 8{m} } } {}.
b. From Eq. 8.7, the torque consists of two terms
T mech = 1 2 i 1 2 dL 11 ( θ m ) m + 1 2 i 2 2 dL 11 ( θ m 90 o ) m T mech = 1 2 i 1 2 dL 11 ( θ m ) m + 1 2 i 2 2 dL 11 ( θ m 90 o ) m size 12{T rSub { size 8{ ital "mech"} } = { {1} over {2} } i rSub { size 8{1} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } \) } over {dθ rSub { size 8{m} } } } + { {1} over {2} } i rSub { size 8{2} } rSup { size 8{2} } { { ital "dL" rSub { size 8{"11"} } \( θ rSub { size 8{m} } - "90" rSup { size 8{o} } \) } over {dθ rSub { size 8{m} } } } } {}
and dL11/mdL11/m size 12{ ital "dL" rSub { size 8{"11"} } /dθ rSub { size 8{m} } } {} can be seen to be the stepped waveform of Fig.8.4b whose maximum values are given by ±Lmax/α±Lmax/α size 12{ +- L rSub { size 8{"max"} } /α} {} (with αα size 12{α} {} expressed in radians!). Thus the torque is as shown in Fig. 8.4c.
c. The peak torque due to each of the windings is given by
T max = L max i 2 = 0 . 128 2 ( π / 3 ) 5 2 = 1 . 53 N . m T max = L max i 2 = 0 . 128 2 ( π / 3 ) 5 2 = 1 . 53 N . m size 12{T rSub { size 8{"max"} } = left [ { {L rSub { size 8{"max"} } } over {2α} } right ]i rSup { size 8{2} } = left [ { {0 "." "128"} over {2 \( π/3 \) } } right ]5 rSup { size 8{2} } =1 "." "53" N "." m} {}
(i) From the plot in Fig. 8.4c, at ***SORRY, THIS MEDIA TYPE IS NOT SUPPORTED.*** , the torque contribution from phase 2 is clearly zero. Although the phase-1 contribution appears to be indeterminate, in an actual machine the torque change from Tmax1, to Tmax1,at θm=0oTmax1, to Tmax1,at θm=0o size 12{T rSub { size 8{"max"1} } ," to " - T rSub { size 8{"max"1} } ,"at "θ rSub { size 8{m} } =0 rSup { size 8{o} } } {}would have a finite slope and the torque would be zero at θ=00θ=00 size 12{θ=0 rSup { size 8{0} } } {}. Thus the net torque from phases 1 and 2 at this position is zero.
Notice that the torque at θm=0θm=0 size 12{θ rSub { size 8{m} } =0} {} is zero independent of the current levels in phases 1 and 2. This is a problem with the 4/2 configuration of Fig. 8.3 since the rotor can get "stuck" at this position (as well as at θm=±90o,±180oθm=±90o,±180o size 12{θ rSub { size 8{m} } = +- "90" rSup { size 8{o} } , +- "180" rSup { size 8{o} } } {}), and there is no way that electrical torque can be produced to move it.
(ii) At θm=45oθm=45o size 12{θ rSub { size 8{m} } ="45" rSup { size 8{o} } } {} both phases are providing torque. That of phase 1 is negative while that of phase 2 is positive. Because the phase currents are equal, the torques are thus equal and opposite and the net torque is zero. However, unlike the case of θm=0oθm=0o size 12{θ rSub { size 8{m} } =0 rSup { size 8{o} } } {}, the torque at this point can be made either positive or negative simply by appropriate selection of the phase currents.
(iii) At θm=75oθm=75o size 12{θ rSub { size 8{m} } ="75" rSup { size 8{o} } } {} phase 1 produces no torque while phase 2 produces a positive torque of magnitude Tmax2Tmax2 size 12{T rSub { size 8{"max"2} } } {}. Thus the net torque at this position is positive and of magnitude 1.53N.m. Notice that there is no combination of phase currents that will produce a negative torque at this position since the phase-1 torque is always zero while that of phase 2 can be only positive (or zero).
  • Example 8.1 illustrates a number of important considerations for the design of VRMs. Clearly these machines must be designed to avoid the occurrence of rotor positions for which none of the phases can produce torque. This is of concern in the design of 4/2 machines which will always have such positions if they are constructed with uniform, symmetric air gaps.
  • It is also clear that to operate VRMs with specified torque characteristics, the phase currents must be applied in a fashion consistent with the rotor position. For example, positive torque production from each phase winding in Example 8.1 can be seen from Fig.8.4c to occur only for specific values of θm. Thus operation of VRMs must include some sort of rotor-position sensing as well as a controller which determines both the sequence and the waveform of the phase currents to achieve the desired operation. This is typically implemented by using electronic switching devices (transistors, thyristors, gate-turn-off devices, etc.) under the supervision of a microprocessor-based controller.
  • Although a 4/2 VRM such as in Example 8.1 can be made to work, as a practical matter it is not particularly useful because of undesirable characteristics such as its zero-torque positions and the fact that there are angular locations at which it is not possible to achieve a positive torque.
  • The analysis of VRMs is conceptually straightforward. In the case of linear machine iron (no magnetic saturation), finding the torque is simply a matter of finding the stator-phase inductances (self and mutual) as a function of rotor position, expressing the coenergy in terms of these inductances, and then calculating the derivative of the coenergy with respect to angular position (holding the phase currents constant when taking the derivative). The electric terminal voltage for each of the phases can be found from the sum of the time derivative of the phase flux linkage and the iR drop across the phase resistance.
  • In the case of nonlinear machine iron (where saturation effects are important), the coenergy can be found by appropriate integration of the phase flux linkages, and the torque can again be found from the derivative of the coenergy with respect to the angular position of the rotor.
  • Although VRMs are simple in concept and construction, their operation is some what complicated and requires sophisticated control and motor-drive electronics to achieve useful operating characteristics.
8.2 PRACTICAL VRM CONFIGURATIONS
  • Practical VRM drive systems (the motor and its inverter) are designed to meet operating criteria such as
  • Low cost.
  • Constant torque independent of rotor angular position.
  • A desired operating speed range.
  • High efficiency.
  • A large torque-to-mass ratio.
  • A compromise must be made between the variety of options available to the designer. Because VRMs require some sort of electronics and control to operate, often the designer is concerned with optimizing a characteristic of the complete drive system, and this will